DATA COLLECTION AND PRESENTATION Table 1: untoughened Data Length, l (m)±0.0005| Time for 20 complete vibrations, t (s) ±0.01| 0.9| 11.5| 11.0| 11.1| 11.0| 11.2| 0.8| 9.0| 9.7| 9.7| 9.2| 9.4| 0.7| 7.6| 7.5| 7.1| 8.0| 7.3| 0.6| 6.8| 6.0| 6.7| 6.0| 6.8| 0.5| 5.0| 5.6| 5.6| 5.1| 4.7| Statement on choice of uncertainties The doubt of the meter rein in is one-half its smallest reading. This ordain be apply throughout: The precariousness of the digital stopwatch used is its smallest reading. This is ± 0.01 s. However the uncertainty used in the calculations shall be the residual effect found from the enough of 5 put down readings. Overview First we shall calculate the clock period T (s) and its uncertainty by calculating the average time for 20 oscillations and split by 20. The same shall be done for the uncertainty in time for 20 oscillations. let Then by victorious the logarithm of both sides we make that Comparing with Miss Whatsthefuzz! We not that; The function y is represent by log T and x is represented by log l. We leave because calculate the value of log T and log l and their uncertainties respectively. By drawing a interpret of log T (y-axis) against log l, we should get a peachy line for which n is the gradient and log k is the y-intercept.
With the avail of the error bars, we will also draw lines of maximum and marginal gradients and from these we shall find the uncertainties in the values of n and k. Sample Calculations all(prenominal) sample calculations have been done for a cantilever continuance of 0.9 m. 1. The average time, tave (s) for 20 oscillations is calcu! lated by summing all the values collected and dividing by 5. i.e; 2. The uncertainty in the average time, tave, is half the difference in the midst of the highest and the lowest of the 5time-readings. i.e; 3. The period of oscillation, T (s) is the a twentieth of the average time. i.e; 4. The uncertainty in the time period, T, is one-twentieth of the...If you want to get a full essay, order it on our website: BestEssayCheap.com
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